Nuprl Lemma : adjacent-nil 11,40

T:Type, xy:T. adjacent(T;[];x;y False 
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ProofTree


Definitions-n, Void, P  Q, False, A, P & Q, A  B, i  j < k, , {x:AB(x)} , {i..j}, Type, s = t, x:A  B(x), x:AB(x), t  T, [], #$n, n+m, l[i], , ||as||, n - m, (x  l), x:AB(x), x:AB(x), adjacent(T;L;x;y)
Lemmasfalse wf, int seg wf

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